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这个术语通常被称为“狂妄的宏伟妄想”，所以请帮我一下： 3n 走过同余类 +1 每一步都偏离对齐 /2 从未改变这个事实积累互质性是“记忆”，它阻止 n 重复。这在 2^k 下是不变的，这使得它能够在混沌中向前推进。耗尽模 3 的同余类迫使 n 变为 2 的幂；游戏结束。我请 AI 证明这些事情，它做到了。我想是这样。那么唯一的问题就是 1.5n 是否能足够快地增长残差向量，以超越穷举的步行。我也问了 AI，得到了一个一页的长篇大论。我甚至不想打出来。我可以用甜言蜜语让 AI 同意几乎任何事情，所以我陷入了困境。这是我知道的唯一一个有着持续深思熟虑对话的论坛，而我无法从中想出解决办法，我还有真正的工作要做。这里有数学家吗？

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The normal term for this is "manic delusion of grandeur", so please help me out:3n walks congruence classes +1 steps each one out of alignment /2 never changes that factAccumulating co-primeness is the "memory" that stops n from repeating. This is invariant under 2^k, which allows it to make forward progress through the chaos. Exhausting congruence classes mod 3 forces n to a power of 2; game over.I asked AI to prove those things, and it did. I assume.The only question then would be if 1.5n can grow the residue vector quickly enough to outrun the exhaustive walk. I asked AI that too, and got back a one page p-word. I'm not even going to type it.I can sweet-talk AI into agreeing with damned near anything, so I'm stuck. This is the only forum I know with consistently thoughtful conversation, and I can't think my way out of this one, and I have real work to do.Is there a mathematician in the house?

我想我知道为什么科拉茨会这样做。